Question

Mole fraction of solute in aqueous HCl solution is 0.2. The molality of HCl solution is​

Answer 1

Answer:

hello dear,

Explanation:

The mole fraction of solute = 0.2 then the mole fraction of solvent = 1- 0.2 = 0.8. Molality = moles of solute/kg solvent; Molar Mass H2O=40 g/kg = (0.8 x40)/1000 = 0.032 Molality = 0.2/0.032 = 6.25.

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Answer 2

Answer:

The molality of the given HCl aqueous solution is found to be 6.85 mol/kg.

Explanation:

Molality may be defined as a solution property and is calculated as the number of solvent moles per kilogram. It’s SI unit is mol/kg.

Now, the Molality of a solution whose mole fraction of solute is known is calculated by the following expression:

$m=\frac{x_B\times1000}{x_A\times M_A}$

where $x_B$ and $x_A$ are the mole fractions of the solute and solvent respectively and $M_A$ is the molar mass of the solvent.

Now, if the mole fraction of solute is 0.2, then the mole fraction of solvent will be 0.8, as the sum of both is unity.

Also, molar mass of HCl is: 1(35.5) + 1(1) = 36.5

Now, substituting everything in the expression given above, we get:

$m=\frac{0.2\times1000}{0.8\times 36.5}$

$m=\frac{200}{29.2}$

Simplifying this, we get:

m = 6.85 mol/kg

Thus, the molality of the given HCl solution is found to be 6.85 mol/kg.

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