mole fraction of solute in aqueous solution of 30% NaOH
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Let the weight of soln be 100gm
weight of Naoh = 30gm
weight of h20 = 70 gm
moles of Naoh= w/m
= 30/40= 3/4
moles of h20 = 70/18= 35/9
total moles = 3/4 + 35/9= 167/36
mole fraction of Naoh= 3/4 ÷ 167/36
= 3/4 x 36/167
= 27/167
Hope this helps.
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weight of Naoh = 30gm
weight of h20 = 70 gm
moles of Naoh= w/m
= 30/40= 3/4
moles of h20 = 70/18= 35/9
total moles = 3/4 + 35/9= 167/36
mole fraction of Naoh= 3/4 ÷ 167/36
= 3/4 x 36/167
= 27/167
Hope this helps.
mark as brainliest please
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