Science, asked by yashreebhatt434, 11 months ago

mole fraction of solute in aqueous solution of 30%urea by mass is


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Answers

Answered by vivekdagale12
4

Explanation:

30% solution of urea signifies in 100g of mixture present 30g is urea present so, 70g of water must be present to make it aqueous mixture of solute and solvent.

Answered by rachana07
1

Answer:

0.116

Explanation:

30% solution means 30gms of urea is present in 100gms of water

that implies 70 gram of water is present

so no of mole of urea (solute)is = 30/60= 0.5

no of moles of water (solvent)is = 70 /18=3.8

mole fraction of urea =

no of moles of solute ÷no of moles of solute + no of moles of solvent

ie 0.5/0.5+3.8= 0.116

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