mole fraction of solute in aqueous solution of 30%urea by mass is
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Answered by
4
Explanation:
30% solution of urea signifies in 100g of mixture present 30g is urea present so, 70g of water must be present to make it aqueous mixture of solute and solvent.
Answered by
1
Answer:
0.116
Explanation:
30% solution means 30gms of urea is present in 100gms of water
that implies 70 gram of water is present
so no of mole of urea (solute)is = 30/60= 0.5
no of moles of water (solvent)is = 70 /18=3.8
mole fraction of urea =
no of moles of solute ÷no of moles of solute + no of moles of solvent
ie 0.5/0.5+3.8= 0.116
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