Question

mole fraction of solute in aqueous solution of NaOHis 0.1 if the specific gravity of the solution is 1.4 then the normality​

Answer 1

Answer:

6.93M

Explanation:

NaOH+H2O

0.1mole 0.9 mole

4g. 16.2g

weight of solution is 20.2 g

Volume of solution is 20.2/1.4×1000

Therefore,

$m = \frac{0.1 \times 1.4 \times 1000}{20.2}$

=6.93 moles