Mole fraction of
the solute in a
1.0 molal aqueous
solution is
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Answer:
Hey Buddy here's ur answer
0.017
Explanation:
Molality is basically number of moles solute present in the 1kg of solvent.
Given clearly that 1 molal of aqueous solution hence the solvent here is water. Therefore 1 mole solute present in the 1 kg of water.
Molefraction is the ratio of the number of moles of solute and total number of moles in solution.
Molecular mass of water (H2O) = 18
Given mass of water = 1000 (1 kg)
Moles = (given mass) / (molar mass) = 1000/18 = 55.5 moles.
Molefraction of solute = (moles of solute) / (total number of moles)
Therefore 1/(55.5+1) = 0.017.
Molefraction of solute in 1 m aqueous solution is 0.017.
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