Question

mole fraction of the solute in a 1.00 molal aqueous solution is ​

Answer 1

$\huge\mathfrak\red{ANSWER}$

Given clearly that 1 molal of aqueous solution hence the solvent here is water. Therefore 1 mole solute present in the 1 kg of water. Molefraction is the ratio of the number of moles of solute and total number of moles in solution. Moles = (given mass) / (molar mass) = 1000/18 = 55.5 moles.

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Answer 2

Explanation:

solution:

Given clearly that 1 molal of aqueous solution hence the solvent here is water. Therefore 1 mole solute present in the 1 kg of water. Molefraction is the ratio of the number of moles of solute and total number of moles in solution. Moles = (given mass) / (molar mass) = 1000/18 = 55.5 moles.

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