Question

Mole fraction of the solute in a 1.00 molal aqueous
solution is
(CBSE AIPMT)
(a) 1.7700
(b) 0.1770
(c) 0.0177
(d) 0.0344
​

Answer 1

Explanation:

Given clearly that 1 molal of aqueous solution hence the solvent here is water. Therefore 1 mole solute present in the 1 kg of water. Molefraction is the ratio of the number of moles of solute and total number of moles in solution. Moles = (given mass) / (molar mass) = 1000/18 = 55.5 moles.