Question

Mole fraction of the solute in a 1.00molal aqueous solutions

Answer 1

https://hi-static.z-dn.net/files/d55/39a55a8217d385ac99c53bf00f02f38b.jpg

Answer 2

Hey dear,

● Answer -
X2 = 0.9474

● Explanation -
# Given -
Molality = 1 m

# Solution -
Molality of a solution is given by -
m = n2 / W1

Hence,
n2/n1 = n2 /(W1/M1)
n2/n1 = M1 × m
n2/n1 = 18 × 1
n2/n1 = 18

Mole fraction of solute is -
X2 = n2 / (n1+n2)
X2 = 1 / (n1/n2+1)
X2 = 1 / (1/18+1)
X2 = 0.9474

Therefore, mole fraction of solute in glucose soln is 0.9474 .


Hope this helped you...