Question

Mole fraction of toulene in it's 25% by mass solution with benzene.

Answer 1

Let mass of benzene = X

Then mass of tauline = 25X/100= X/4 =

Molar mass of benzene = 78u

Molar mass of tauline = 92u

No of moles of benzene = weight / molar mass = X/78 moles =

No of moles of tauline = X/4/92 = X/368 = 0.00272moles

Total moles = X/78 + X/368 = 0.0155X moles

Mole fraction of tauline = no of moles of tauline / total no moles = .00272X/.0155X = 0.175

Ans =0.18

(Is this ans right or wrong?)