mole fraction of urea in 0.1M solution
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- Mole fraction of urea =0.1
- so the solution contains 0.1moles of urea dissolved in 0.9moles of water
- MOLARITY(m)is defined as the number of moles of SOLUTE dissolved in 1000g of SOLVENT
- so number of moles of urea present in (1000g) 55.55 =6.1728m
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Explanation:
moles of urea =given mass /molar mass = 6/60=0.1. thus, mole fraction of 6g urea in 100 ml water=0.1/5.55+0.1=0.1/5.65=0.0176.
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