Question

Mole fraction of water vapour in the water saturated air is 0.02. If total pressure is 1.2 atm, partial pressure of dry air is

Answer 1

Answer:1.176

Explanation:

Pdry gas = ptotal-po2

Po2=ptotal*Xo2 ==1.2*0.02== 0.024

Pdry gas= 1.2-0.024== 1.176

Answer 2

The partial pressure of dry air is 1.176atm.

Given: Mole fraction of water vapour in the water-saturated air is 0.02 and the total pressure is 1.2 atm.

To find: We have to find the partial pressure of dry air.

Solution:

Let partial pressure of dry air is x.

Now partial pressure of dry air is a difference between total pressure and partial pressure of oxygen.

Now partial pressure of oxygen will be-

$P_{O_2}=1.2×0.02\\=0.024$

Now partial pressure of dry air will be-

x=1.2-0.024

x=1.176

The value of x is 1.176.

Thus, the partial pressure of dry air is 1.176atm.