Question

Mole fraction ofc3h5(oh)3(glycerine) in a solution of 36 g of water and 46 g of glycerine is

Answer 1

Answer:

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Molar mass of glycerine = 92 g

Molar mass of glycerine = 92 gNumber of moles of glycerine = 46g/92g = 0.5 mol

Molar mass of glycerine = 92 gNumber of moles of glycerine = 46g/92g = 0.5 molMolar mass of water = 18 g

Molar mass of glycerine = 92 gNumber of moles of glycerine = 46g/92g = 0.5 molMolar mass of water = 18 gNumber of moles of water = 36/18g =2 moles

Molar mass of glycerine = 92 gNumber of moles of glycerine = 46g/92g = 0.5 molMolar mass of water = 18 gNumber of moles of water = 36/18g =2 molesTotal number of moles in solution = 0.5 + 2 = 2.5 mol

Molar mass of glycerine = 92 gNumber of moles of glycerine = 46g/92g = 0.5 molMolar mass of water = 18 gNumber of moles of water = 36/18g =2 molesTotal number of moles in solution = 0.5 + 2 = 2.5 molMole fraction of glycerine = moles of glycerine /total number of moles of glycerine = 0.5 /2.5 = 0.2

Molar mass of glycerine = 92 gNumber of moles of glycerine = 46g/92g = 0.5 molMolar mass of water = 18 gNumber of moles of water = 36/18g =2 molesTotal number of moles in solution = 0.5 + 2 = 2.5 molMole fraction of glycerine = moles of glycerine /total number of moles of glycerine = 0.5 /2.5 = 0.2Answer = 0.2