Question

Mole friction of the solute in a 1.00 molal aqueous solution is

Answer 1

1 Molal means 1 mole in 1000g of a solution
here we have aqueous solution which is water
so it means 18g (1 mole)of Water in 1000g of solution
Now first finding the moles of water
No of moles=given mass /Mol mass
=1000/18
=55.55
Now here water is solvent so it's mole are 55.55 because it has more quantity that is why we choose it as our solvent
Now moles of solute are given which is 1
now finding the mole fraction
Mole fraction=

moles of solute/moles of solute+moles of solvent
= 1/1+55.55
=0.0177

Answer 2

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1 Molal = 1 mole of solute and 1000 g of a solution

here we have aqueous solution which is water

here,it means 18g (1 mole)of Water in 1000g of solution

Now first finding the moles of water

No of moles=given mass /Molecular mass

=1000/18

=55.55

Now here water is solvent so it's mole are 55.55 because it has more quantity that is why we choose it as our solvent

Now moles of solute are given which is 1

now finding the mole fraction

Mole fraction=Moles of solute/moles of solute+moles of solvent

= 1/1+55.55

=0.0177

Hope it will help u

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