Question

mole of atoms present in 2240ml of CO2 at STP is ?​

Answer 1

Answer:

molar mass of gas at STP = 22.4 litres

1 litre = 1000 ml

22.4 litre = 22.4 × 1000 = 22400 ml

molar mass of co2 at STP = 44×22400 gm

no. of moles = 56÷ 44 × 22400

= 0.11 moles

no. of molecules = moles × avogadro no.

= 0.11 × 6.022 × 10 raised to the power 23

= 66.242 × 10 raised to the power 21 molecules

hopefully it is the answer

Answer 2

Answer:

Molar mass of gas at STP = 22.4 liters

We know that

1 liter = 1000 milliliter

Molar mass of CO2 at STP = 44 × 22,400gm .

Number of moles = 56 / 44 × 22,400

===> 56/22,400 × 44

===> 0.0025 × 44

===> 0.11 moles

Number of molecules = moles × Avogadro number

===> 0.11 moles × 6.022 × ( 10 ) 23

===> 11/100 × 6,022 / 1000 × ( 10 ) 21

===> 11 × 6,022 / 1000 × ( 10 ) 21

===> 66,242 / 1000 × ( 10 ) 21

===> 66.242 × ( 10 ) 21 molecule .

Hope this helps you .