Question

Mole of electrons present in 9 gram of aluminium is

Answer 1

Answer:

26.09*10^23

Explanation:

Moles of al=9/27=0.33

No of atoms =0.33Na

=0.33*6.022*10^23

=2.007*10^23

One atom of al contains 13 electrons

Hence total no of electrons =13*2.007*10^23

=26.09*10^23