Question

mole of the sulphuric acid lost during discharge is​

Answer 1

Answer: 2.83 moles of the sulphuric acid lost during discharge is​

Explanation:

Now here,

The formula of Sulfuric Acid = $H_2SO_4$

Let's assume that 1 Liter of sulphuric acid is present in the battery

solution. Due to this, the density of sulfuric acid fells from 1.294 to 1.139 gm/L

From the above,  $H_2SO_4$    of density 1.294gm/L are 39% and the of density 1.139gm/L is 20% by weight.

$H_2SO_4$

Therefore,

For discharge of the battery, first, we are required to find out the initial number of moles of sulfuric acid and after that final number of moles of sulfuric acid,

An initial number of moles of sulphuric acid before discharge =  $\frac{1294X0.39}{98}$     = 5.15 moles

Now a final number of moles of sulphuric acid after discharge = $\frac{1139 X 0.20}{98}$ = 2.32 moles

From the above

The number of moles of sulphuric acid lost during discharge = 5.15 − 2.32        = 2.83 moles.

Hence, 2.83 moles of sulphuric acid were lost during the discharge of any battery.

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