Question

Molecular formula: C10H15N; 1H NMR (CDCl3)  6.9 and 6.6 (AA’BB’ pattern, 4H, J = 8.0 Hz), 3.5 (broad singlet, 2H, D2O exchangeable), 2.5 (t, 2H, J = 7.5 Hz), 1.5 (quintet, 2H, J = 7.5 Hz), 1.3 (sextet, 2H, J = 7.5 Hz), 0.9 (t, 3H, J = 7.5 Hz).​

Answer 1

Answer:

Explanation:

= 5.5, 4.1 Hz), 3.81 (dd, 1H, J = 4.1, 2.5 Hz), 7.52 (d, J = 8Hz, 2H), ... 1.11 (t, 6H), 1.29 (d, 6H), 2.40 (q, 4H), 2.55 (t, 2H), 2.65 (t, 2H), 3.12 (septet, ... H NMR (δ, CDCl3): 2.0 (brs, 1H, exchangeable with D2O), 3.73 (s, 3H), 4.79 (s, 2H) ...