Question

Molecular formula of a compound is C6 H18 O3. Find its emperical formula.
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Answer 1

Answer:

C2H6O is the emperical formula of C6H18O3

Answer 2

The empirical formula of the given compound is $C_2H_6O$

Explanation:

Empirical formula is defined as the formula in which the atoms in a compound are present in lowest whole number ratio.

We are given:

Molecular formula of the compound = $C_6H_{18}O_3$

To make the atoms to the lowest whole number value, we divide the atoms of each element by '3'

Empirical formula of the compound = $C_{(6/3)}H_{(18/3)}O_{(3/3)}=C_2H_6O$

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