Question

Molecular formula of compound in which carbon is equal to 55% hydrogen is equal to 9% and vapour density is equal to 88%

Answer 1

You suppose to have 100 g of this compound. Now divide each mass for its atomic mass. You obtain:

#C= (54.4 g)/(12g/(mol))= 4,53# mol of atom

#H= (9.1 g)/(1/(mol))= 9.1#mol of atom

#O= (36,4 g)/(16/(mol))= 2.275#mol of atom

now let's divide all the results for the smaller one. You have

C=2; H=4; O=1 that is the minimum formula but its MM should be (12 x 2 + 1 x4+16)= 44 g/mol that is the half of the given molecular mass. Hence the compound you are looking for is

C4H8O2. It can be the butirric acid