Question

molecular formula of the given question............?

Answer 1

C=41.37 H=5.75 N=16.09 Vapor density=43.3
So M=2V.D=86.6 O=36.8

Let find the empirical formula....just divide by molecular mass

C=41.37/12=3.44

H=5.75/1=5.75

N=16.09/14=1.15

O=36.8/16=2.3

No divide all by 1.15 to make it into whole number...

C=3.44/1.15=3
H=5.75/1.15=5
N=1
O=2

So E.F=C3H5O2N So emperical mass=86.6

Also Molecular mass is 86.6

So M.F=E.F

So Molecular formula : C3H5O2N


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