Question

Molecular mass of a Gas 50.5amu calculate it density at 293k on 0.973 atm pressure

Answer 1

Use d = pm ÷ RT
D = 0.973 × 50.5 ÷ 0.0821 ×293
D = 2.04


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Answer 2

Molecular mass of a Gas 50.5amu, the density at 293k on 0.973 atm pressure is 0.01.

Given:

Molecular mass = 50.5amu

Temperature = 293K

Pressure = 0.973atm

To find:

Density = ?

Concept used:

Ideal gas law:

This is law for state of hypothetical ideal gas. It has been stated by Benoit Paul Emile Clapeyron in the year 1834. This law is the combination of Charles's law, Boyle's law, Avogadro's law and Gay-Lussac's law. It is also known as General gas equation.

Formula to be used:

PV = nRT

Here, P = Pressure, V = Volume, R = Rydberg's constant, T = Temperature and n = number of moles.

Since, $n = \frac{mass}{Molecular mass}$

$PV = [\frac{mass}{molecular mass} ]RT\\\\P[molecular mass] = [\frac{mass}{volume}]RT\\ \\0.973[50.5] = [\frac{mass}{volume}][8.314][566]$

Since, $Density = \frac{Mass}{Volume}$

Density = 0.01

Therefore, Molecular mass of a Gas 50.5amu, the density at 293k on 0.973 atm pressure is 0.01.