Question

Molecular mass of an organic solvent, "p is 46u. "p is used to remove chlorophyll from the leaf in the lab. (a) Identify "P" (b) Write the equations when "P" is oxidized. (i) in the presence of oxidising agent (ii) in the absence of oxidising agent (c) "p reacts with the product formed in the reaction (b) ) given above, which forms a fruity smelling compound. (i) Write the equation for the same. (ii) Fruity smelling compound is treated with an alkali. Name the process (d) Explain the cleansing action of soap. 

Answer 1

a) ethanol
b)ch3ch2 oh + o=ch3cooh + h 2o
c)ch3 cooh + c2 h5 oh = ch3 coo c2 h5 + h2o
d)ester
ii)ch3cooc2 h5 + naoh = ch3 coona + c2 h5 oh

Answer 2

Welcome dear,

● Answers -
(a) Compound P is ethanol (C2H5OH)

(b) (i) In absence of oxidizing agent, ethanol oxidises to ethanal.
C2H5OH + [O] ---> CH3CHO + H2O

(ii) In presence of oxidizing agent, ethanol oxidizes to ethanoic acid.
C2H5OH + 2[O] ---> CH3COOH + H2O

(c) (i) Ethanol reacts with ethanoic acid to give ethyl ethanoate (fruity odour).
C2H5OH + CH3COOH ---> C2H5COOCH3 + H2O

(ii) Reaction of ester with base is called saponification.

(d) Cleansing action of soap -
- Soap breaks up the oil into smaller drops, which can mix with the water.
- It works because soap is made up of molecules with two very different ends - hydrophilic and hydrophobic end.
- Hydrophobic ends of soap molecule attach to the oil.
- Hydrophilic ends stick out into the water.
- This forms micelles which are easily removed with water.

Hope this helps you...