Question

Molecular mass of ferric sulphate

Answer 1

Answer:

399.88 g/mol

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Answer 2

Answer:

Molar weight of Fe=56 g

Molar weight of S=32 g

Molar weight of O2=32 g i.e.Molar weight of O=16 g

Therefore,

molar weight of ferric sulphate is:- (2*56)+3*(32+4*16)=400 g

Now, 400 g of ferric sulphate is 1 mol

1 g of ferric sulphate is 1/400 mol

40 g of ferric sulphate is (1/400)*40=0.1 mol

So,40 g of ferric sulphate has 0.1 mol of it.