Chemistry, asked by triangle2996, 6 months ago

Molecular mass of oxygen is 32. Calculate the number of oxygen atoms present in 64 g of oxygen?

Answers

Answered by Vishal101100

2

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1 mole O = 32 g

then no of moles in 64 g = 64/32 = 2 moles.

then

in one mole = 6.022×10²³ Atoms.

no of atoms in 2 moles =

2×6.022×10²³ atoms = 12.044×10²³ atoms.

Answer = 12.044×10²³ atoms.

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Answered by nandhini5964

0

Answer:

24.088*10^23 atoms

Explanation:

one mole of any substance have 6.023*10^23 constituents.

so calculate how moles of oxygen are there in 64 g of Oxygen...that is given mass/ molecular mass of oxygen =64/16=4

since one mole has 6.023*10^23 atoms ...

4 mole has 6.023*10^23*4 ...=24.088*10^23 atoms

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