Molecular mass of oxygen is 32. Calculate the number of oxygen atoms present in 64 g of oxygen?
Answers
Answered by
2
1 mole O = 32 g
then no of moles in 64 g = 64/32 = 2 moles.
then
in one mole = 6.022×10²³ Atoms.
no of atoms in 2 moles =
2×6.022×10²³ atoms = 12.044×10²³ atoms.
Answer = 12.044×10²³ atoms.
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Answered by
0
Answer:
24.088*10^23 atoms
Explanation:
one mole of any substance have 6.023*10^23 constituents.
so calculate how moles of oxygen are there in 64 g of Oxygen...that is given mass/ molecular mass of oxygen =64/16=4
since one mole has 6.023*10^23 atoms ...
4 mole has 6.023*10^23*4 ...=24.088*10^23 atoms
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