Chemistry, asked by sunnysaini2705, 11 months ago

Molecular orbital diagram of ne2 and explain

Answers

Answered by jhanvichampawat
1

Formation of N

2

molecule: Electronic Configuration,

σ1s

2

<σ∗1s

2

<σ2s

2

<σ∗2s

2

<[π2p

x

2

=π2p

x

2

]<<σ2p

z

2

Bond order = (N

b

−N

a

)/2=(10−4)/2=3

Bond order indicates the number of bonds in diatomic molecule is 3, hence TripleBond

Formation of F

2

molecule: Electronic Configuration:

σ1s

2

<σ∗1s

2

<σ2s

2

<σ∗2s

z

2

σ∗2pz

2

<[π2p

x

2

=π2p

x

2

]<[π∗2p

x

2

=π∗2p

x

2

]<σ2p

z

Bond order = (N

b

−N

a

)/2=(10−8)/2=1

Single bond F−F.

Formation of Ne

2

molecule: Electronic Configuration,

σ1s

2

<σ∗1s

2

<σ2s

2

<σ∗2s

z

2

<σ∗2pz

2

<[π2p

x

2

=π2p

x

2

]<[π∗2p

x

2

=π∗2p

x

2

]<σ2p

z

2

Bond order = (N b

−N a

)/2=(10−10)/2=0

Hence, no bond between Ne atoms.

Explanation:

I hope it helps you

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