Question

Molecular weight of a compound containing 15% Be by mass is 2700 u. The number of Be atoms present in one molecule of compound is (atomic mass of Be is 9 u)
(1) 40
(2) 45
(3) 35
(4) 30​

Answer 1

Answer:

418.58 g/mol

Answer and Explanation: The molar mass of Ag3PO4 A g 3 P O 4 is calculated as follows: 107.87 x 3 + 30.97 + 16.00 x 4 = 418.58 g/mol.

Answer 2

The number of Be-atoms that are present in 1 molecule of a compound are 45

Explanation:

We are given:

Molecular weight of the compound = 2700 u

Mass percent of Beryllium in the compound = 15 %

Mass of Beryllium in the compound = $\frac{2700\times 15}{100}=405u$

It is also given,

Mass of 1 Beryllium atom = 9 u

To calculate the number of Beryllium atoms in the compound, we use the equation:

$\text{Number of Be-atoms in compound}=\frac{\text{Mass of Be in compound}}{\text{Mass of 1 Be-atom}}$

Putting values in above equation, we get:

$\text{Number of Be-atoms in compound}=\frac{405}{9}=45$

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