Molecular weight of a gas is 44.The volume occupied by 2.2grams of the gas
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first we should find which gas is this is . Then it will be easy to solve this problem. It will be NO2
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number of moles of gas =22/44 one mol of gas 22.4 at ntp pv=nrt p1v1/ p2v2 = n1/n2 =v2. p1/p2 . n1/n2.v1 =22.4/20×2 therefore v2= 0.56 liters
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