Question

Molecular weight of a gas that diffuses twice as rapidly as the gas with molecular weight 64 is

Answer 1

Take A as a compound of unknown mass and B as known mass. Rate of diffusion of A is 2×Rate of diffusion of B.
As,r is inversely proportional to √M
$ra \div rb = \sqrt{mb} \div \sqrt{ma}$
$2b \div b = \sqrt{64} \div \sqrt{m}$
$2 = 8 \div \sqrt{m}$

$\sqrt{m} = 8 \div 2 = 4$
$m = 16$
Hence, the mass of A is 16

Answer 2

Answer:

Explanation:

Answer is 16

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