molecular weight of Ca(Na3)2
Ca = 40 , Na = 23 Ans. is 164
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Explanation:
The molar mass of Ca(NO3)2
=40.1+2×(14+3(16))=40.1+2×(62)=164.1g/mol.
1 mole (164.1 g) of calcium nitrate will contain 6 moles of O atoms.
The atomic mass of oxygen is 16 g/mol.
6 moles of oxygen atoms corresponds to 6×16=96g.
The percent of oxygen in calcium nitrate =
164.1
96×100
=58 %.
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