Question

molecular weight of gas ,11.2 litres of which at 1 atm & 273 K weight 32 g is​

Answer 1

Answer:Hey mate...... .

Here's ur answer :::""

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Given : Volume (V) = 11.2 L

Wt. of gas (W) = 32 g

Molecular Wt. (M) = ?

»» At STP,

» no. of moles of gas = Volume / 22.4

» no. of moles = 11.2/22.4

» no. of moles = 0.5 moles

›› we have,

no. of moles = Wt. of gas /mol. Wt.

.°. 0.5 = 32 / M

.°. M = 32/0.5

.°. »»» M = 64 g/moles «««

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