Question

Molecular weight of NaCl is 58.5. A solution of NaCl containing 5.85 g NaCl per litre is:
(A) 1 molar
(B) 0.1 molar
(C) 2 molar
(D) 0.585molar​

Answer 1

Answer:

B - 0.1M

Explanation:

Explained in the pic.

Answer 2

Answer:

The molarity of the given solution of sodium hydroxide is equal to 0.1molar.

Therefore, the option (B) is correct.

Explanation:

Given : The molecular weight of NaCl $M=58.5gmol^{-1}$

The mass of sodium chloride present in the solution $m=5.85g$

Volume of the solution, $V=1L$

Number of moles of solute (NaCl), $n=\frac{m}{M} =\frac{5.85}{58.5}$

Number of moles of NaCl = 0.1 moles

Molarity of solution = (Number of moles of NaCl)/(Volume of solution in L)

Molarity $=\frac{0.1mol}{1L}=0.1molL^{-1}$

Therefore, the molarity of the solution is 0.1 molar.