Question

molecular weight of NaHCO3

Answer 1

Molecular weight = Sum of the atomic masses of elements

$\tt{NaHCO_3 = m_{Na} + m_H + m_C + 3m_O}$

$\tt{= 23 + 1 + 12 + 3 ( 16 )}$

$\tt{= 23 + 1 + 12 + 48}$

$\tt{= 84 \ grams}$

Answer 2

Na- Sodium 23

H -Hydrogen 1

C -Carbon 12

O- Oxygen 16

NaHCO3-}23+1+12+(16*3)=84 grams

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