Question

Molecule
Na2X
on treatment with dilute sulphuric acid forms a molecule ‘Y’ and liberates a rotten smelling gas. The liberated gas undergoes a double decomposition reaction with molecule ‘Z’, forming a black precipitate and vinegar. Identify the groups in Y and Z.​

Answer 1

Answer:

The compound Z is Na

2

CO

3

.It reacts with dil.H

2

SO

4

and liberates a colourless gas which does affect potassium dichromte solution. The gas evolved is carbon dioxide. Hence, carbonate radical may be present.