Question

moles of agcl formed when 17 g agno3 is mixed with 1.435 g nacl​

Answer 1

Answer: 0.02

Explanation:

Here Nacl is limiting reagent

So 1.435 ÷ 58.5 = 0.02

Answer 2

molar mass of AgNO3 = 170g/mol

molar mass of NaCl = 58.5 g/mol

molar mass of AgCl = 143.5 g/mol

chemical reaction is ...

$AgNO_3+NaCl\rightarrow AgCl+NaNO_3$

1 mole of AgNO3 reacts 1 mole of NaCl

or, 170g of Ag reacts with 58.5 g of NaCl

or, 17g of Ag reacts with 5.85 g of NaCl

but here only 1.435g of NaCl is given.

hence, NaCl is limiting reagent.

now, 1 mole of NaCl forms 1 mole of AgCl.

or, 58.5 g of NaCl forms 143.5 g of AgCl.

or, 1.435 of NaCl forms 143.5/58.5 × 1.435 = 3.52g of AgCl.

now, mole of AgCl = weight in gm/molar weight of AgCl

= 3.52/143.5

= 0.0245