Moles of electron present in 64g of CH4
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Given mass=64g
Molar mass=16g
No. Of molecules =(64/16)*N
Where N is avogadro no.
No. Of electrons in 1 C atom=6 amd in 4 H atoms=4
Electrons in one molecule =10
Total electrons=10*No. Of molecules
Molar mass=16g
No. Of molecules =(64/16)*N
Where N is avogadro no.
No. Of electrons in 1 C atom=6 amd in 4 H atoms=4
Electrons in one molecule =10
Total electrons=10*No. Of molecules
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