Question

Moles of KClO3 required for producing sufficient O2 to react with 1 mole of aluminium will be

Answer 1

Hello Dear.

Here is the answer---

Reaction of the Decomposition of Potassium Chlorate →

2KClO₃ ----→ 2KCl +3O₂ 

Reaction of Aluminium with Oxygen →

4Al + 3O₂ ---→ 2Al₂O₃

Now,
From the Second Reaction,

 ∵ 4 moles of Aluminum Requires 3 moles of Oxygen.
∴ 1 moles of Aluminum requires 3/4 moles of Oxygen.

Now, 
From the First Equation,
∵ 3 moles of Oxygen is produced by the 2 moles of Potassium Chlorate.
∴ 1 moles of Oxygen is Produced by the 2/3 moles of KClO₃.
∴ 3/4 moles of O₂ is produced by the (2/3) × (3/4) moles of KClO₃.
   = 1/2 moles of KClO₃.
  = 0.5 moles of KClO₃.

∴ Moles of KClO₃ Required is 0.5 moles.


Hope it helps.

Answer 2

Answer:

Explanation:

Reaction of the Decomposition of Potassium Chlorate →

2KClO₃ ----→ 2KCl +3O₂ 

Reaction of Aluminium with Oxygen →

4Al + 3O₂ ---→ 2Al₂O₃

Now,

From the Second Reaction,

 ∵ 4 moles of Aluminum Requires 3 moles of Oxygen.

∴ 1 moles of Aluminum requires 3/4 moles of Oxygen.

Now, 

From the First Equation,

∵ 3 moles of Oxygen is produced by the 2 moles of Potassium Chlorate.

∴ 1 moles of Oxygen is Produced by the 2/3 moles of KClO₃.

∴ 3/4 moles of O₂ is produced by the (2/3) × (3/4) moles of KClO₃.

   = 1/2 moles of KClO₃.

  = 0.5 moles of KClO₃.

∴ Moles of KClO₃ Required is 0.5 moles.

Hope it helps.