Question

moles of O atoms in 9.00 g of Mg (NO3)2​

Answer 1

Answer:

$3.75 \times {10}^{22}$

Explanation:

let the equation

Mg(no3)2=== mgo+2no2+1/2o2

at wt of mg(no3)2 is 144g

it gives 16g of oxygen

so then 9g of mg(no3)2 gives =16/144×9

=1g of oxygen

moles of 1g of oxygen is 1/16=0.0625moles

to get no of oxygen atoms we want to multiply moles with avagadro number then we get the answer....