Chemistry, asked by ayeshashabbir6600, 7 months ago

Moles of O atoms in 9.00g of Mg(NO3)2

Answers

Answered by basitchemist

9

Answer:

0.364moles

Explanation:

Mg (NO3)2 = MgN2O6= 24+28+96= 148

moles of Mg (NO3)2 = 9\148

O in one mole 6 so = 9x6 \148 =0.364moles

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