Question

moles of o2 produced on complete decomposition of1.5moles of kclo3​

Answer 1

hello!

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balanced equation for this is:

balanced equation for this is:2KClO3 ————- 2KCl + 3O2

2KCl + 3O2So the answer is 3 moles of O2 is given

2KCl + 3O2So the answer is 3 moles of O2 is givenBut if we want to go further to calculate the mass of O2 given,

2KCl + 3O2So the answer is 3 moles of O2 is givenBut if we want to go further to calculate the mass of O2 given,Molar mass of KClO3 = 39 + 35.5 + 3 (16) = 122.5

2KCl + 3O2So the answer is 3 moles of O2 is givenBut if we want to go further to calculate the mass of O2 given,Molar mass of KClO3 = 39 + 35.5 + 3 (16) = 122.5Molar mass of O2 = 32

2KCl + 3O2So the answer is 3 moles of O2 is givenBut if we want to go further to calculate the mass of O2 given,Molar mass of KClO3 = 39 + 35.5 + 3 (16) = 122.5Molar mass of O2 = 322 moles of KClO3 ———— 3 moles of O2

3 moles of O22(122.5) of KClO3 ———— 3(32) of O2

3(32) of O2245g of KClO3 __________96g of O2

96g of O2Thus 1.225g of KClO3 ————— x

96g of O2Thus 1.225g of KClO3 ————— x x = 1.225 * 96 ÷ 245 = 0.48g

so, 0.48g of O2 is given