Question

moles present in 3.5kg of Na OH​

Answer 1

Answer:

we know that

moles = given mass / molar mass

here given mass = 3.5 kg = 3500 g

molar mass = 40g

so moles - 3500 / 40 = 87.5 moles

Answer 2

Answer:

Atomic number

Na=23

O =16

H=1

NaOH

23+(16×1)

23+16

39

we can divide mole present in a kg

39÷3.5=11.14

Hope this answer helpyou