Molten aluminium was poured in a sand mould and the thickness of the solid skin formed after 20 seconds and 50 seconds were found to be 3 mm and 4.5 mm respectively. What would be the thickness of the solid skin at the end of 100 seconds after pouring?
Answers
Given Molten aluminium was poured in a sand mould and the thickness of the solid skin formed after 20 seconds and 50 seconds were found to be 3 mm and 4.5 mm respectively. What would be the thickness of the solid skin at the end of 100 seconds after pouring?
We know that skin thickness is given by
t = t ₁√z + t₂
3 = t₁ √20 + t₂
3 = 4.472 t₁ + t₂--------(1)
Similarly we have
4.5 = t₁√50 + t₂
4.5 = 7.07 t₁ + t₂---------(2)
Solving (1) and (2) we get
4.472 t₁ + t₂ = 3
7.07 t₁ + t₂ = 4.5
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- 2.598 t₁ = - 1.5
So t₁ = 0.577
t₂ = 0.418
Substituting these values in the above equation we get
t = t₁√z + t₂
t = 0.577 x √100 + 0.418
t = 6.188 mm
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