Question

momemtum of a body of mass 12kg moving with velocity 5m/sec is​

Answer 1

Answer:

For a perfectly elastic collision, coefficient of restitution is e=1.

Let u and v be the velocities of 10 kg and 1 g masses after collision.

Thus, e=  

rel. vel. of approach

rel. vel.of separation

​  

=  

5−0

v−u

​  

=  

5

v−u

​  

 

But, as e=1, we have v−u=5.

Total momentum before collision is P=10×5=50 kg m/s

Total momentum after collision is P=10×(v−5)+0.001×v=10.001v−50

Thus, 10.001v−50=50⇒v=  

10.001

100

​  

≈10 m/s

Explanation:

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Answer 2

Answer:

p = 60Kg.m/s

Explanation:

Mass (m) = 12kg

Velocity (v) = 5m/s

Thus,

Momentum (p) = Mass(m) × Velocity(v)

p = mv

=> p = 12 × 5 = 60Kg.m/s