Question

moment of force.
A boy weighing 300N exerts a pressure of 200 N/m' on the ground. Calculate his area of contact
with the ground.
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Answer 1

Answer:

PRESSURE = FORCE/AREA

FROM THIS WE GET AREA =FORCE/PRESSURE

SO AREA =300/200 m²

AREA = 3/2 m² OR 1.5m²

PLEASE MARK AS BRAINLIST PLEASE

Answer 2

Given:

• Weight, w = 300N
• Pressure, P = 200N/m²

Find:

• Area of contact with the ground, A

Solution:

we, know that

$\small\boxed{ \sf P = \dfrac{w}{A} }$

where,

• P = 200N/m²
• w = 300N

So,

$\small{ \to\sf P = \dfrac{w}{A} }$

$\small{ \to\sf 200 = \dfrac{300}{A} }$

Do, Cross-multiplication

$\small{ \to\sf 200A = 300}$

$\small{ \to\sf A = \dfrac{300}{200} }$

$\small{ \to\sf A = \cancel{ \dfrac{300}{200} } = \dfrac{3}{2} }$

$\small{ \to\sf A = \dfrac{3}{2} = 1.5 {m}^{2} }$

$\small{ \to\sf A = 1.5 {m}^{2} }$

$\small{ \underline{ \therefore \sf Area = 1.5 {m}^{2} }}$