Question

moment of force of 50 Newton about a point is 2.5 Newton meter. find the perpendicular distances by force from the point

Answer 1

Solution:

Force applied = 25 N

\bot distance from the point of rotation = ?

Moment of force = Force \times \bot distance

2.5 = 25 \times \bot distance

distance = 2.5/25 = 1/10 m = 10 cm

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