Moment of inertia for a rectangular lamina about the axis in the plane of lamin passing through the end and parallel to the breath is
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comment me whether i am write or wrong although the concept I have used is correct
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Use the formula for MI of a triangle about one of its side. The diagonal splits the rectangle into 2 congruent triangles. You should get the result -:
MI of rectangle about its diagonal = M(a^2)(b^2)/[6(a^2)+(b^2)]
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