Question

Moment of inertia of a body is 1 kg m^2. If the body makes 2 revolutions per second,then its angular momentum is

Answer 1

$4\pi \: kg {m}^{2} {s}^{ - 1}$

Explanation:

$Given, \: \: \: I = 1 \: kg{m}^{2} \: \: \: and \: \: \: n = 2 {s}^{ - 1} \\ we \: \: know \: \: \boxed{ \omega = 2\pi n \: \: \: and \: \: \: angular \: \: momentum = I \omega} \\ Now, \: \: \: angular \: \: momentum =I \omega = I \times 2\pi n \\ = 1 \:kg {m}^{2} \times 2\pi \times 2 {s}^{ - 1} \\ = \boxed{4\pi \: kg {m}^{2} {s}^{ - 1} }$