moment of inertia of a circular ring of radius r about its polar axis is
Answers
Answer:
Our apps
LEARNING APP
ANSWR
CODR
XPLOR
SCHOOL OS
11th
Physics
Systems of Particles and Rotational Motion
Moment of Inertia
The moment of inertia of a ...
PHYSICS
The moment of inertia of a circular ring(radius R, mass M) about an axis which passes through tangentially and perpendicular to its plane will be?
A
2
MR
2
B
MR
2
C
2
3
MR
2
D
2MR
2
MEDIUM
ANSWER
Based on the above figure, Let's consider, I
AB
= Moment of inertia of ring about tangent
I
AB
= I
Z
+MR
2
=
2
1
MR
2
+MR
2
=
2
3
MR
2
Answered By
toppr
How satisfied are you with the answer?
This will help us to improve better
answr
Get Instant Solutions, 24x7
No Signup required
DOWNLOAD APP
More Questions by difficulty
EASY
MEDIUM
HARD
Prev Question
Next Question
Related Questions to study
The moment of inertia of semicircular ring about an axis which is perpendicular to the plane of the ring and passes through the center.
View Answer
A cylinder is rotated clockwise and lowered slowly on a rough inclined plane with(μ=0.8). Then:
View Answer
VIEW MORE
Revise with Concepts
Formulae for the Moment of Inertia of Certain Regular Bodies
EXAMPLE
DEFINITIONS
FORMULAES
Learn with Videos
Moment of Inertia of 1-D Bodies
16 min
Moment Inertia of Two Dimensional Bodies - I
7 min
VIEW MORE
Quick summary with Stories
Moment of inertia of One Dimensional bodies
2 mins read
Moment of Inertia of 2D Bodies
3 mins read
VIEW MORE
CLASSES
Class 5
Class 6
Class 7
Class 8
Class 9
Class 10
Class 11 Commerce
Class 11 Engineering
Class 11 Medical
Class 12 Commerce
Class 12 Engineering
Class 12 Medical
BOARDS
CBSE
ICSE
IGCSE
Andhra Pradesh
Bihar
Gujarat
Jharkhand
Karnataka
Kerala
Madhya Pradesh
Maharashtra
Punjab
Rajasthan
Tamil Nadu
Telangana
Uttar Pradesh
EXAMS
JEE Main
JEE Advanced
UPSEE
BITSAT
TS Eamcet
WBJEE
VITEEE
MHT-CET
SAT
IJSO
NDA
NEET
AIIMS
AP Eamcet
COMEDK
JIPMER
BCECE
KCET
KEAM
IMO
IEO
HBBVS
CA Foundation
CS Foundation
CMA Foundation
CLAT
AILET
ICO
ICSO
NTSE
NSO
NSTSE
KVPY
PLANS
Basic
Advanced
Ultimate
MODULES
Online Classes
Mock Tests
Adaptive Practice
Live Doubts
FEATURES
Video classes
All India test series
Stories
Previous papers
Live classes
Create your own tests
24/7 Help
Expert tutors
SOCIAL
Stay upto date with our Newsletter!
Stay informed, stay ahead. Be a topper
Subscribe
About Us
Brand Resources
Press
Customer Stories
Jobs
Educators
Fellowship
Learning Planet
Guides
Ask
Blog
Bytes
News
Terms of Service
Privacy Policy
Contact Us
FAQs
India
Answer:
According to the theorem of perpendicular axis. thus the movement of inertia of ring about any of its diameter is MR22.
Explanation:
pls like me and follow me