Question

moment of inertia of a combination of ring and disc of same mass M and same radius are kept in contact about the tangent passing through point of contact and in plane of both Ring and disc​

Answer 1

Answer:

7MR^2/2.

Explanation:

Since, the disk given in the question is of mass M and radius R so the moment of inertia of the disk passing through the center will be  MR^2/2. So, by using the parallel axis theorem we can find the moment at the tangential position of the disk. So, the moment of inertia at the tangent position of the disk will be MR^2/2 + MR^2 which on solving we will get 3MR^2/2.

The moment of inertial of the ring through the center is MR^2 and through the tangent will be MR^2 + MR^2=2MR^2.

So, the total moment when the ring and disk are in combination will be 3MR^2/2 + 2MR^2 which on solving we will get 7MR^2/2.

Answer 2

Answer:

Explanation:

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