Physics, asked by amanminz0, 4 months ago

Moment of inertia of a ring about an axis passing through its center and perpendicular to its plane:
1 point
I = 1/2 MR²
I = 2/5 MR²
I = 2/3 MR²
I = MR²​

Answers

Answered by ijazasgar7
1

Answer:

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Answered by atulsinghrajput27
1

Answer:

I=MR^2

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