Moment of inertia of a rod about an axis passing through its one of end with their derivatation
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Moment of Inertia (MI) of a rod about an axis passing its one end=1/3×ML^2 where M =mass of rod, L=length of the rod
- Derivation:
if mass of the rod = M
length=L
we know that MI of that rod about an axis through its middle point and perpendicular to the rod=1/12×ML^2
Now applying parallel axis theorem,
if the required MI of rod is= I
then according to the theorem,
I=1/12×ML^2+ M×(L/2)^2
or, I = 1/12×ML^2+ 1/4×ML^2
or, I= (1/12+1/4)ML^2
or, I= 1/3×ML^2
(Proved)
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